2023 KAKAO BLIND RECRUITMENT개인정보 수집 유효기간

유효기간을 체크해 해당 번호를 출력하는 문제이다.

def solution(today, terms, privacies):
    answer = []
    today = today.split('.')
    today = int(today[0])*12*28 + int(today[1])*28 +int(today[2])
    terms = { term.split()[0]:int(term.split()[1])*28 for term in terms}
    for i, privacy in enumerate(privacies):
        day,term  = privacy.split()
        day = day.split('.')
        day = int(day[0])*12*28 + int(day[1])*28 +int(day[2])
        day += terms[term]
        if(today >= day):
            answer.append(i+1)
    return answer

이분은 split를 안쓰고 리스트컴프리핸스와 if문을 사용해서 간단히 줄였다.

def to_days(date):
    year, month, day = map(int, date.split("."))
    return year * 28 * 12 + month * 28 + day

def solution(today, terms, privacies):
    months = {v[0]: int(v[2:]) * 28 for v in terms}
    today = to_days(today)
    expire = [
        i + 1 for i, privacy in enumerate(privacies)
        if to_days(privacy[:-2]) + months[privacy[-1]] <= today
    ]
    return expire